Photoelectric effect and free electrons

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Shining a specific color of light on a metal causes the expulsion of free electrons, leading to a discussion on whether this process constitutes ionization. The key point is that while electrons are expelled, the metal does not become ionized in the traditional sense because the outermost electrons in metals are delocalized, meaning they are not bound to individual atoms. This results in a situation where no single atom loses an electron, and thus, there are no isolated charged atoms. Although the metal may become charged due to the loss of these delocalized electrons, the term "ionization" is typically reserved for individual atoms or molecules, not for the collective behavior of electrons in a metallic structure.
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When we shine a light of particular color on a metal,it expells the free electrons present in the metal.In that case,doesn't the metal get ionized ?
 
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Depends on what you exactly mean by ionization. You won't be able to point to ions. There are no isolated, charged atoms, rather every single atom misses a piece of an electron.
 
Borek said:
There are no isolated, charged atoms, rather every single atom misses a piece of an electron.
Can you elaborate more on that ? And you say they "miss a piece of electron", why can't that be called ionisation ?
 
Docscientist said:
Can you elaborate more on that ? And you say they "miss a piece of electron", why can't that be called ionisation ?
In a metal, the outermost electrons are delocalised rather than bound to an individual atom, so no single metal atom loses an electron.
 
Vagn said:
In a metal, the outermost electrons are delocalised rather than bound to an individual atom, so no single metal atom loses an electron.
What do you mean by delocalised ?
 
Docscientist said:
What do you mean by delocalised ?
Have you tried the wikipoedia page on delocalized electrons?
 
Vagn said:
Have you tried the wikipoedia page on delocalized electrons?
I just went through the page.I still can't get it.Even if it is delocalized,it is still a free electron that once belonged to the metal's atoms.So any way there is a losing that takes place.In that case,considering the metal to be ionized should be right,isn't it ?
 
Docscientist said:
I just went through the page.I still can't get it.Even if it is delocalized,it is still a free electron that once belonged to the metal's atoms.So any way there is a losing that takes place.In that case,considering the metal to be ionized should be right,isn't it ?

The metal will be charged unless it replaces the missing electron, but we don't say that the metal is ionized. That terms is usually reserved for single atoms and sometimes molecules.
 
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