Photoelectric Effect: Doubts Answered

AI Thread Summary
When photons strike a metal surface with sufficient frequency, they transfer energy to electrons, allowing them to overcome binding energy and be emitted. The discussion clarifies that electrons are not "ripped off" but rather ejected due to energy absorption. Concerns about momentum conservation are addressed, noting that the total momentum of the system, including the measuring apparatus and the Earth, must be considered. The momentum of the incident photons contributes to the overall system, but the mass of the equipment makes its effect negligible. The complexities of momentum conservation in this context do not require significant concern.
Karan Punjabi
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Hey I have a doubt that when on a metal surface photon falls then electrons are ripped off if the photon has frequency equal to or more than threshold frequency but photon falling on electron has a downward momentum and elctron rips off in a upward momentum...how is it possible according to law of conservation of linear momebtum?
 
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hi there

firstly, the electrons are not "ripped off". They gain energy from the interaction of the absorption of the photons.
When an electron in the material material absorbs the energy of one photon and acquires more energy than the electron binding energy to hold it within that atom structure, it is ejected/emitted.

Dave
 
Karan Punjabi said:
according to law of conservation of linear momebtum
The conservation of momentum (or explaining how and where it is involved) is not really an issue here. The total momentum of the whole measuring apparatus would need to be conbnsidered. The incident photons carry momentum which will turn up as an increase in momentum of the equipment or even the Earth. The momentum of the original photons also needs to be considered with regard with where they were originally produced.
It's easier to ignore all this as the mass of the equipment is so much greater than that of the photons.
Don't lose any sleep over this one.
 
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