Photoelectric Effect: Doubts Answered

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SUMMARY

The discussion addresses the photoelectric effect, specifically the interaction between photons and electrons on a metal surface. When a photon with a frequency equal to or greater than the threshold frequency strikes a metal, it transfers energy to an electron, allowing it to overcome its binding energy and be emitted. The conservation of momentum is acknowledged, noting that the momentum of the incident photons is negligible compared to the mass of the measuring apparatus, making it a non-issue in practical terms.

PREREQUISITES
  • Understanding of the photoelectric effect
  • Knowledge of photon energy and frequency
  • Familiarity with electron binding energy
  • Basic principles of conservation of momentum
NEXT STEPS
  • Research the mathematical formulation of the photoelectric effect
  • Explore the implications of conservation of momentum in photon-electron interactions
  • Study the threshold frequency concept in various metals
  • Investigate experimental setups for demonstrating the photoelectric effect
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Physics students, educators, and researchers interested in quantum mechanics and the behavior of light and matter interactions.

Karan Punjabi
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Hey I have a doubt that when on a metal surface photon falls then electrons are ripped off if the photon has frequency equal to or more than threshold frequency but photon falling on electron has a downward momentum and elctron rips off in a upward momentum...how is it possible according to law of conservation of linear momebtum?
 
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hi there

firstly, the electrons are not "ripped off". They gain energy from the interaction of the absorption of the photons.
When an electron in the material material absorbs the energy of one photon and acquires more energy than the electron binding energy to hold it within that atom structure, it is ejected/emitted.

Dave
 
Karan Punjabi said:
according to law of conservation of linear momebtum
The conservation of momentum (or explaining how and where it is involved) is not really an issue here. The total momentum of the whole measuring apparatus would need to be conbnsidered. The incident photons carry momentum which will turn up as an increase in momentum of the equipment or even the Earth. The momentum of the original photons also needs to be considered with regard with where they were originally produced.
It's easier to ignore all this as the mass of the equipment is so much greater than that of the photons.
Don't lose any sleep over this one.
 

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