Photoelectric Effect: Frequency vs. Amplitude

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The photoelectric effect demonstrates that the energy of emitted electrons is directly proportional to the frequency of incident light rather than its amplitude. Each ejected electron interacts with a single photon, meaning energy transfer is frequency-dependent. Higher amplitude indicates a greater number of photons, but does not increase the energy of individual electrons. Only at extremely high intensities, such as those produced by powerful lasers, might electrons interact with multiple photons. This reinforces the principle that frequency is the key factor in determining electron energy in the photoelectric effect.
rictor
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How energy of the emitted electron is proportional to the incident light frequency but not to its amplitude according to photoelectric effect?
 
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Because each ejected electron has only interacted with one photon. Thus the energy depends only on the frequency of that photon. Higher amplitude just means more photons falling onto the material. As far as I know, until you get to really, REALLY high intensities, the kind you can only get from extremely powerful lasers, the chances of an electron interacting with more than one photon at a time is essentially zero.
 
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Thread 'Motional EMF in Faraday disc, co-rotating magnet axial mean flux'

Thread 'Motional EMF in Faraday disc, co-rotating magnet axial mean flux'

So here is the motional EMF formula. Now I understand the standard Faraday paradox that an axis symmetric field source (like a speaker motor ring magnet) has a magnetic field that is frame invariant under rotation around axis of symmetry. The field is static whether you rotate the magnet or not. So far so good. What puzzles me is this , there is a term average magnetic flux or "azimuthal mean" , this term describes the average magnetic field through the area swept by the rotating Faraday...
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