Photoelectric effect violating entropy?

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Discussion Overview

The discussion revolves around the implications of the photoelectric effect in photovoltaic cells within an isolated system, specifically addressing concerns about entropy and energy conversion. Participants explore the theoretical framework of thermal radiation, energy transfer, and the potential violation of the second law of thermodynamics.

Discussion Character

  • Debate/contested
  • Conceptual clarification
  • Exploratory

Main Points Raised

  • One participant describes a scenario where a photovoltaic cell is placed in a container of gas, questioning whether the conversion of thermal energy to electric potential reduces the system's entropy.
  • Another participant suggests examining the efficiency of the photoelectric effect at finite temperatures, proposing that increased temperature may lead to an equilibrium that prevents energy transfer.
  • A later reply emphasizes that introducing the capacitor into the system alters its closed nature, potentially invalidating the initial assumptions about entropy.
  • Concerns are raised about the implications of energy conversion on the second law of thermodynamics, particularly regarding the definition of closed systems.

Areas of Agreement / Disagreement

Participants express differing views on the nature of the system and the implications for entropy. There is no consensus on whether the scenario presented violates the second law of thermodynamics, and the discussion remains unresolved.

Contextual Notes

Participants highlight the importance of system boundaries and the conditions under which energy transfer occurs, indicating that assumptions about the closed nature of the system may need reevaluation.

Smacal1072
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Hey all,

I posted this a week or so ago, but never really got closure on this issue:

Photovoltaic cells utilize the photoelectric effect to produce a voltage whenever an incident photon's energy is higher than the band gap of the silicon used for the cell.

Consider an isolated system, say a container of gas. If the temperature of the gas is above 0 K, the gas particles produce thermal radiation in the form of photons. The energy of these photons are distributed according to Planck's law. Regardless of the temperature of this gas, there will always be some high-energy photons radiated by the gas. Since we're assuming the system is isolated, none of these photons leave the system.

Let's say we throw in a photovoltaic cell into this container, which is connected to an ideal capacitor with infinite capacitance. Let's say the capacitor is outside of the system. Photons radiated by the gas with energy above that of the band gap generate a tiny voltage in the cell by the photoelectric effect, which charges the capacitor. Over time, the hot gas cools, since some of it's higher-energy radiation is being converted to electric potential (similar to evaporation of water).

Assuming all of this is OK so far, the problem is: How is this possible? Isn't this reducing the entropy of the system, by directly converting thermal energy of the system into electric potential? Something seems wrong.

I appreciate your help!
 
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The first thing I'd check is the nature of the photoelectric effect in materials at finite (i.e., nonzero) temperature. If the efficiency of the photoelectric effect decreases with increasing temperature, you may have your answer right there. We would obviously expect an equilibrium between the gas and the solid, with no energy being transferred.

You might check, for example, "Photoelectric Effect" (Chapter 5), Handbook of Physics, ed. by E. U. Condon and Hugh Odishaw. Also see Robert T. Ross, "Thermodynamic Limitations on the Conversion of Radiant Energy into Work," J. Chem. Phys. 45 (1) (1966) and Ross and Ta-Lee Hsiao's "Limits on the yield of photochemical solar energy conversion," J. Appl. Phys. 48(11) (1977) which addresses the analogous question of photovoltaics. (Note: I haven't studied these resources; I'm suggesting them because they might help you find the answer for yourself.)
 
Smacal1072 said:
Assuming all of this is OK so far, the problem is: How is this possible? Isn't this reducing the entropy of the system, by directly converting thermal energy of the system into electric potential? Something seems wrong.
You drew a system boundary and then penetrated it, so it isn't a closed system anymore!
 
Smacal1072 said:
Assuming all of this is OK so far, the problem is: How is this possible? Isn't this reducing the entropy of the system, by directly converting thermal energy of the system into electric potential? Something seems wrong.
You drew a system boundary and then penetrated it, so it isn't a closed system anymore! The second law says, "The entropy of an isolated (ie, closed) system..."

So what happens if you locate the capacitor inside the system...?
 

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