Photon emission from dipole antenna

Click For Summary
SUMMARY

Photons are emitted from the electric field generated by stationary protons in a dipole antenna, despite the protons not accelerating. The antenna primarily emits coherent states rather than single-photon Fock states, which resemble classical electromagnetic waves. When the intensity is reduced to average photon numbers near or below one, the coherent state approaches the vacuum state, leading to a Poisson distribution of photon emissions. This distribution is defined by the formula $$P(N)=\frac{\lambda^N}{N!} \exp(-\lambda)$$, where ##\lambda## represents both the average photon number and its standard deviation.

PREREQUISITES
  • Understanding of electromagnetic wave theory
  • Familiarity with dipole antennas and their operation
  • Knowledge of coherent states and Fock states in quantum mechanics
  • Basic grasp of Poisson distribution in statistics
NEXT STEPS
  • Study the principles of electromagnetic wave propagation in dipole antennas
  • Explore the differences between coherent states and Fock states in quantum optics
  • Learn about the statistical properties of photon emissions, focusing on Poisson distribution
  • Investigate advanced antenna designs for single-photon emission capabilities
USEFUL FOR

Physicists, electrical engineers, and researchers in quantum optics who are interested in the behavior of dipole antennas and photon emission characteristics.

Danyon
Messages
83
Reaction score
1
Are photons emitted from the stationary protons in a dipole antenna? The protons don't accelerate at any point but their electric field does contribute to the electromagnetic wave.
 
Last edited:
Physics news on Phys.org
Photons are the energy quanta of the (classical) EM wave and one of the known sources of EM wave is the antenna.
Danyon said:
The protons don't accelerate at any point but their electric field does contribute to the electromagnetic wave.
Are protons the only charged entity inside the metal making up the antenna?
 
It's impossible to make usual antennas to emit single-photon (Fock) states. What you'll emit are coherent states, which are more like a classical electrical wave than single-photon Fock states. If dimmed down to intensities with average photon numbers close (or even less than) one, the coherent state consists to a large amount of the vacuum state. With some small probability you may register one or (to even lesser probability) more photons in a statistical way. The probability distribution for the photon number in such a coherent state is the Poisson distribution,
$$P(N)=\frac{\lambda^N}{N!} \exp(-\lambda),$$
where ##\lambda## is both the average number ##\langle N \rangle=\lambda## of registered photons as well as its standard devition ##\langle N^2 \rangle -\langle N \rangle^2=\lambda##.
 
  • Like
Likes   Reactions: blue_leaf77

Similar threads

  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 15 ·
Replies
15
Views
4K
  • · Replies 18 ·
Replies
18
Views
2K
  • · Replies 38 ·
2
Replies
38
Views
7K
  • · Replies 6 ·
Replies
6
Views
3K
Replies
11
Views
2K
  • · Replies 8 ·
Replies
8
Views
812