rbj said:
but this is correct:
E0 = m0c2
no?
Yes. That is quite correct and is identical to what I wrote as you can see by noting that the
m I used in the above expression, i.e. E
0 = mc
2, is identical to the one you used here, i.e. m
0.
i dunno, but anything can be misused.
While you're correct it is not what I had in mind. Nearly every single relativity text and article I've read on mass has made the error of implying that E
0 = m
0c
2 holds in every concievable circumstance, which it does not. I'm not absolutely certain how this came to be but I'm pretty sure its a result of students beleiving that newer texts are better than older ones in certain ways. I agree that in a lot of cases that is true. But what is missing is certain generalities that have not made it into newer texts. The general case of mass is a perfect example. E.g. for continuous media the mass is completely defined by the stress-energymomentum tensor and, in the most general case, the mass density is not proportional to the energy density. Since this seems to have been missed by most relativity authors then readers of those texts never learn about it. Thus when one studies general relativity one can easily become confused, or at least come to the wrong conclusions, regarding the fact that the active gravitational mass of matter is a function of both energy and pressure. I.e. inertial mass depends on pressure and pressure is a source of gravity.
i think the blanket and unqualified statement that "photons are massless particles" leads more (lay) people to error and contradiction than having a concept of relativistic mass vs. "proper" mass (or "invariant mass" or whatever they be calling it).
I agree. If someone simply says either "photons are massless particles" or "photons have mass" then they are not learning the full story. Learning only part of a theory and its comnsequences is bound to lead one to make errors. I've seen too many people on physics forums/newsgroups take the notion that "photons have no mass" and conclude from that that "light does not generate a gravitational field" which of course it does.
Regarding
invariant mass vs
proper mass; Caution is warranted here. These two terms should not be confused with each other. Typically the term
invariant mass is used to refer to the value of the total 4-momentum of a system where
proper mass refers to the value of the 4-momentum of a single particle. As such the invariant mass of a particle equals the proper mass. I learned this from Hans C. Ohanian, one of the authors of
Gravitation and Spacetime - 2nd Ed., i.e. that invariant mass is a term used for a system of particles. Its unclear to me if he extended that to systems containing both particles and fields but I assume this to be the case.
.. but if the only mass in our semantic is the rest mass, i think that leads most lay physikers and beginners into saying some pretty dumb things than if such concepts and differentiation were made.
I think people will make mistakes when they only learn part of the ramifications of a theory, no doubt. Ideally one will make very few errors if they have studied it in general and completely, and that includes studying the stress-energy-momentum tensor. For the beginner this tensor can be avoided by studying certain derivations which were first done by Einstein. Unfortunately those derivations are hard to find. I can show you such a derivation if you'd like?
Best wishes
Pete