Thomas2054 said:
I may be on a wild goose chase here, but I am looking for a physical definition of a complex angle, i.e., an angle of the form a + bi. Is there such a beast or is a complex angle purely a mathematical construct?
Thanks.
Thomas
Hello there. I found this old thread when I was looking for the same information. This turned up in a Google search, and it looked like a promising lead, but nobody seems to have given a simple answer, so I made up my own. Caveat: I'm neither a physicist nor a mathematician. Anyway, in case you're still around and still interested, consider this:
First, a messy answer:
Suppose you have a complex number
a such that
a = x + yi = r*e^i*theta.
Draw a ray from the origin through point
a. Follow the unit circle counterclockwise from the positive x-axis to the point where it intersects the ray. The length of this arc is theta, the real angle. Now take a half-turn to the left and measure the distance from the intersection point to point
a. This is the messy part: You must measure this distance using the logs of the distances from the origin to the two points, ln 1 for the intersection point and ln r for point
a, and subtracting: (ln 1) - (ln r). This simplifies to -ln r, and it is the imaginary portion of the complex angle.
That's a physical definition of sorts, but not very satisfying, I fear. So I have come up with what I think is a better answer:
Let us move to what I call the exponential plane. (Maybe proper mathematicians call it something else, but I haven't found another name for it . . .) I mean a Cartesian plane where each point (x', y') represents e^(x' + iy'). In other words, complex number
a, where
a = x + yi = r*e^i*theta = e^(ln r + i*theta), which is represented by point (x, y) on the complex plane, is represented on the exponential plane by ln
a, which is equal to ln r + i*theta, or in other words, by point (x', y'), where x' = ln r and y' = i*theta. (I know the ln function is multivalued, but I believe that doesn’t affect this particular discussion. We can just use the principal value of ln and leave it at that, no?)
Adding the real and imaginary portions of the complex angle -- let's call it "xang" for short -- from the "messy" part above, we get xang
a = theta + i*(-ln r). See the connection? In the exponential plane, the complex angle of
a can be measured physically by (1) following the y-axis from the origin to point (0, y') to get the real part of the angle and (2) taking a half-turn to the left and measuring the horizontal distance from the y-axis to point (x', y') to get the imaginary part of the angle. With this orientation, moving up/down gives positive/negative real values, and moving left/right gives positive/negative imaginary values for the complex angle.
Finally, let me note in passing that xang
a = (ln
a)/i
This may not be original, though I haven't seen it elsewhere. Then again, it may not be right . . .
FWIW
Jeremy Whipple
a translator in Tokyo