Physics 2 Electric Fields, Circuits, Magnetism

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SUMMARY

The discussion focuses on solving a practice test related to electric fields and circuits in Physics 2. For part 1a, the user correctly applies the formula E = kq/r², substituting +Ze for q when r < R, resulting in E = kZe/R². In part 1b, the user accurately concludes that the electric field E is zero when r > R, as the enclosed charge within the Gaussian surface cancels out (+Ze and -Ze). These calculations demonstrate a solid understanding of Gauss's Law and electric field concepts.

PREREQUISITES
  • Understanding of Gauss's Law
  • Familiarity with electric fields and their calculations
  • Knowledge of the concepts of enclosed charge
  • Basic proficiency in algebra and physics equations
NEXT STEPS
  • Study the applications of Gauss's Law in different geometries
  • Learn about electric field lines and their significance
  • Explore the relationship between electric fields and potential energy
  • Investigate the principles of circuits involving capacitors and resistors
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Adeel Ahmad
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Can someone please help me out with this practice test and provide explanations?
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So for number 1 a, when r<R, I take +Ze as q and plug it into the equation E = kq/r2 and get E = kZe/R2. Not sure if that's correct
 
Then for number 1 b when r>R, I assume that E is zero since you set a Gaussian surface that encloses the entire thing so you take the enclosed charge which would be zero since it is +Ze and -Ze which cancels. So when you plug that into solve for E, you would get zero. Please lmk if this is correct.
 

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