Physics Assesment : Copper wires resistance

AI Thread Summary
The discussion focuses on understanding the resistance of copper wires for a GCSE physics assessment. Key factors affecting resistance include the wire's length, thickness, and the material's resistivity, summarized by the formula R = ρL/A. To make accurate predictions, it's important to gather specific measurements of the wire, including its length and cross-sectional area. The relationship between voltage, current, and resistance is also highlighted through Ohm's Law, emphasizing that longer wires have higher resistance while thicker wires have lower resistance. Accurate predictions may require measuring the wire's actual resistance with a multimeter to account for real-world variables.
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Hi. This may seem extremely easy for all you guys here but seeing as I am 15 its not quite as simple to me.
Firstly the assesment I am going to be doing will count for my GCSE therefore i want the best possible result (Btw I am taking triple science)
Can someone with as much detail as possible explain a good "prediction" since I am not 100% sure if the thing I am writing is correct therefore i need some help :S thanks
 
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We can help you as soon as you ask the problem. From what I can tell it has something to do with the resistance of copper wires (i'm a smart one, ain't I? :smile: ) I don't know if this helps, but the resistance will depend on the thickness of the wire, it's length and a constant of resistivity (or something along those lines, I'm not checking any of this, so make sure you verify it), in the form:

<br /> R = \rho \frac{L}{A}

where p is the constant (depends on the material, look up copper), L is the length, A is the cross-sectional area, and R of course is resistance.
 


Sure, I would be happy to help you with your assessment on copper wire resistance. First, let's start with some background information. Resistance is a property of a material that describes how easily it allows electricity to flow through it. It is measured in ohms (Ω). The resistance of a material depends on several factors, including the material's length, cross-sectional area, and temperature.

To predict the resistance of a copper wire, we need to understand Ohm's Law, which states that the current through a conductor is directly proportional to the voltage and inversely proportional to the resistance. In other words, the longer the wire, the higher the resistance, and the thicker the wire, the lower the resistance.

To make a good prediction for your assessment, you will need to gather some information about the copper wire you will be using. This includes its length, cross-sectional area, and temperature. You can measure the length of the wire using a ruler or measuring tape. The cross-sectional area can be calculated by measuring the diameter of the wire and using the formula A = πr², where A is the cross-sectional area and r is the radius of the wire.

Once you have this information, you can use the formula R = ρl/A, where R is the resistance, ρ (rho) is the resistivity of copper (1.68 x 10^-8 Ωm), l is the length of the wire, and A is the cross-sectional area. This formula will give you the predicted resistance of the copper wire.

However, keep in mind that this prediction is based on the assumption that the wire is made of pure copper and is at room temperature. In reality, there may be impurities in the copper wire and the temperature may affect its resistance. To get a more accurate prediction, you can measure the actual resistance of the wire using a multimeter.

I hope this explanation helps you make a good prediction for your assessment. Remember to include all the relevant information and calculations in your prediction to support your answer. Good luck!
 
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