Physics Challenge Question: Stability on a Cylinder

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SUMMARY

The discussion centers on calculating the stability range of a solid cube placed on a cylinder, where the cube has a side length of ##l = r*pi/2## and the cylinder has a radius of ##r##. Participants emphasize the importance of analyzing the center of mass in relation to the pivot point to determine the angle at which the cube will tip over. A recommendation is made to express the potential energy of the cube as it rocks on the cylinder to find stable and unstable equilibrium positions. The problem is framed as one that does not require calculus, focusing instead on geometric relationships.

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IDValour
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Homework Statement


A solid cube of side ##l = r*pi/2## and of uniform density is placed on the highest point of a cylinder of radius ##r## as shown in the attached figure. If the cylinder is sufficiently rough that no sliding occurs, calculate the full range of the angle through which the block and swing (or wobble) without tipping off. (You can assume this range of equilibrium positions is stable).

Homework Equations



None that I've been made aware of.

The Attempt at a Solution



I'm trying to consider this in terms of a point at which the center of mass is directly above the axis of rotation but I'm struggling from there to be honest. Stability isn't something we've covered in my spec, so I'm not sure I have the knowledge to tackle this. I tried drawing a couple diagrams but I didn't get far.
 

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I would recommend writing an expression for the potential energy of the cube as it rocks on the cylinder. You can find the stable and unstable equilibrium by differentiating the expression.
 
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The source of this problem claims not to need calculus of any form.
 
IDValour said:
calculate the full range of the angle through which the block and swing
Did you mean to type 'through which the block can swing'?

If sliding is assumed not to happen then the question becomes one of at what angle does the block topple over, when balancing on the midpoint of its lowest side (the pivot point). Think about the relationship between the centre of gravity of the block, the pivot point and the direction of the force of gravity.
 
IDValour said:
I'm trying to consider this in terms of a point at which the center of mass is directly above the axis of rotation ...

Yes, I think that's the key idea.
Draw a picture corresponding to this special configuration.
 
Last edited:

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