Physics help on minimum stopping distance

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To determine the minimum stopping distance for a 6000 kg load on a truck traveling at 20 m/s, the maximum horizontal force exerted by the brackets is 8000 N. Using Newton's second law, the acceleration can be calculated as a = F/m, resulting in an acceleration of approximately 1.33 m/s². The stopping distance can be derived from the kinematic equation, which relates initial velocity, acceleration, and distance. The calculated minimum stopping distance ensures the load does not slide forward into the cab. This problem highlights the application of physics principles in real-world scenarios.
emily69_420
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I am having a huge problem with this physics problem...I just can't figure it out. Please help me if you can.
Heres the problem:
A load of steel with a mass of 6000 kg rests on a flatbed of a truck. It is held in place by metal brackets that can exert a maximum horizontal force of 8000 N. When the truck is traveling 20 m/s, what is the minimum stopping distance if the load is not to slide foreward into the cab?
 
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Zz.
 
F = ma
a_{avg}=\frac{\Delta v}{\Delta t}
 
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