How Fast Would a Car Be Moving with the Same Energy as a Pound of Body Fat?

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A pound of body fat contains approximately 4100 kcal, which converts to about 1.72e7 Joules. To find the speed of a 1400 kg car with this amount of kinetic energy, the formula KE = 0.5mv² is used. By solving the equation, the resulting speed is calculated to be approximately 156.58 m/s, equivalent to about 350 mph. The key steps include converting kcal to Joules and applying the kinetic energy formula. Understanding these calculations provides insight into the relationship between energy content and speed.
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a pound of body fat has an energy content of about 4100 kcal. if a 1400kg automobile had an equivalent amount of translational kinetic energy, how fast would is be moving?
<.447 m/s = 1mph, 1kcal= 4186j>

I really don't know how to approach this question if someone could show me step by step how to do it I would appreciate it, so I can learn how to do it.

thanks
 
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If 1Kcal = 4186J then 4100 Kcal = 1.72e7 J
KE = .5mv2
1.72e7 = .5(1400)v2
v = 156.58m/s = 350mph
 
Thanks for the reply could you provide the basic formulas for me you used to solve this?

thanks
 
The only one I really used was the Ke = .5mv^2 that I listed above. I just converted the Kcal to Joules, That is the KE, the rest is solving for v
 
ok thanks
 
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