Physics — Net work on a box being pulled…

AI Thread Summary
To calculate the net work on a 5 kg box being pulled up a 5 m inclined plane at a 53-degree angle, it's essential to consider the forces acting on the box, including the applied force, normal force, and gravitational force. The work done by the applied force can be calculated using the formula W = F * d * cos(θ), while the work done by gravity is negative due to the height change. A free-body diagram is crucial for visualizing the forces and their directions, which helps clarify the calculations. The confusion arises from not properly defining the forces and their respective work contributions. Understanding these concepts is fundamental to solving the problem correctly.
Arsana
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Homework Statement


How to calculate the net work

Homework Equations


A 5 kg box is pulled with a force F = 100 N for 5 m long inclined plane. The height of the inclined plane is 4 m and angle of inclination is 53^

a) What is a work done by force F?

b) What is the work done normal force N?

c) What is the work done by gravitational force ?

d) What is the net work done on the box?

The Attempt at a Solution


First I tried to find a) one. I multiplied 100 * 5 * cos(53) = 300,90
2) N = mg cos(53) ; N = 5 * 10 * cos (53) = 30.090
3) Wg = -mg h
Wg = -200
4) ...?
I found all of the formulas in internet and now I am confused, because it seems like I have done nothing right. If you know that, answer me, please!
 

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Arsana said:
I multiplied 100 * 5 * cos(53)
What direction is the applied force in?
Arsana said:
2) N = mg cos(53) ; N = 5 * 10 * cos (53) = 30.090
That's the normal force, but the question asks for the work done by it. How do you calculate the work done by a force?
 
haruspex said:
direction
There is nothing about direction on the picture
 
haruspex said:
work done by a force?
Work = Mass * Gravity * Height
 
Arsana said:
Wg = -200
With g=10m/s2, that is correct.
 
Arsana said:
There is nothing about direction on the picture
You have a picture? Can't you tell the direction from that? Basically, is the force horizontal or parallel to the slope?
Arsana said:
Work = Mass * Gravity * Height
That's for the work done by gravity. What about a force in general?
 
Arsana said:

Homework Statement


How to calculate the net work

Homework Equations


A 5 kg box is pulled with a force F = 100 N for 5 m long inclined plane. The height of the inclined plane is 4 m and angle of inclination is 53^

a) What is a work done by force F?

b) What is the work done normal force N?

c) What is the work done by gravitational force ?

d) What is the net work done on the box?

The Attempt at a Solution


First I tried to find a) one. I multiplied 100 * 5 * cos(53) = 300,90
2) N = mg cos(53) ; N = 5 * 10 * cos (53) = 30.090
3) Wg = -mg h
Wg = -200
4) ...?
I found all of the formulas in internet and now I am confused, because it seems like I have done nothing right. If you know that, answer me, please!

There's a severe problem with the way you attempt to solve this problem. If this is what you are accustomed to, you have not understood anything. What you wrote in your solution are mostly undefined (i.e. what is "N", "W", etc..?).

You define these things (and the directions) by making a free-body diagram! This is a MUST in any problem like this (my students are required to show it and they will not receive full credit if the sketch is missing).

So start in the beginning and draw the free-body diagram!

BTW, why are you hunting through the "internet" for the relevant equations? Don't you come across them in class or in your text?

Zz.
 
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