Physics problem involing a lotus car

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SUMMARY

The discussion focuses on calculating the distance traveled by a Lotus car driven at an average speed of 20 m/s, experiencing a drag force of 400 N. The mass of the vehicle is 903 kg, and the fuel conversion efficiency is 13%. The calculations reveal that the acceleration is 0.443 m/s², leading to a distance of approximately 451.47 meters using the work-energy principle. The forum emphasizes the importance of applying the correct equations, specifically suggesting the use of work = force * distance instead of traditional equations of motion.

PREREQUISITES
  • Understanding of Newton's second law (F=ma)
  • Familiarity with kinematic equations (V^2=U^2 + 2as)
  • Basic knowledge of work-energy principles
  • Concept of fuel conversion efficiency
NEXT STEPS
  • Study the work-energy theorem in detail
  • Explore advanced applications of drag force in vehicle dynamics
  • Learn about fuel efficiency calculations in automotive engineering
  • Investigate the impact of vehicle mass on acceleration and distance
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Students studying physics, automotive engineers, and anyone interested in vehicle performance calculations and energy efficiency analysis.

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Homework Statement



When the a lotus is driven at average speed of 20 m/s the drag force on the vehicle is 400N. If the average fuel conversion is 13% then calculate the distance traveled by the vehicle.

Mass of Vehicle = 903kg
Volume of fuel tank= 43.5 litre
Density of fuel= 775 kg/m^3
Calorific Value of fuel= 42.7 MJ/kg



Homework Equations



F=ma and V^2= U^2 + 2as



The Attempt at a Solution




(1)400=903a
a= 0.443m/s^2

(2) V^2= U^2 +2as
20^2+2(0.443)s
S= 451.47m
 
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I think you can forget equations of motion. This appears to be about work and energy. Try an equation like...

Work = force * distance
 

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