Physics Revision: Evaluating Questions & Finding Formulas

AI Thread Summary
The discussion focuses on solving physics problems related to a mass suspended from a spring. The initial extension of the spring is calculated using the formula mg = kx, resulting in an extension of 0.784 meters. The upward acceleration after pulling the mass down an additional 5 cm is determined to be 0.625 m/s². The velocity of the mass as it passes through the equilibrium position is found to be 5.16 m/s, while the period of oscillation cannot be calculated due to missing frequency information. The conversation emphasizes the importance of understanding the concepts rather than just seeking answers.
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I am doing some revision for physics and can't evaluate these questions, can anybody help or give a formula.

Q1.

A mass of 2.2 Kg is suspended from a spring of spring constant K = 25 Nm^-1
What is the initial extension?

Q2.

The mass (in Q1) is pulled down a further 5cm and released.
What is the initial upward acceleration?

Q3.

Calaculate the velocity of the mass as it passes through the equilibrium position.

Q4.

What is the value of period?


Thanks so much :-)
 
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Have you tried solving any of these questions yourself?
 
Im new to physics but yes i have tried
 
What have you tried using? :smile: At least the first question is very simple, but if you are not able to understand it or answer it, how do you expect to understand the other questions? I am not trying to put you down or anything. It's for your own good, really.

"Give a man a fish; you have fed him for today. Teach a man to fish; and you can sell him fishing equipment."
 
force= k*x
mg=kx
2*9.8=25*x
Initial extension is 0.784m
k*x-mg=m*acceleration
25*(0.784+0.05)-2*9.8=2*acceleration
acceleration=0.625m/s^2
work=force*distance cos angle
since the force and the displacement are in the same direction, then
work of spring=0.5*k*x^2-0.5kx^2
=0.5*25(0)-0.5*25*(.784+.05)=-10.425joule
work due to gravity is mgh-mgh=0-2*9.8*(.784+.05)=16.3joule
total work= 10.425+16.3=26.7joule
work=change in kinetic energy=.5(mV^2-mV^2)=.5(2V^2-0)
26.7=v^2
v=5.16m/s
period= 1/frequency
frequency=number of cycles/time
the number of cycles is not give in the example
i think it is supposed to be in the example
anyway i hope that this solution would be correct as i beleive...actually think so
best wishes

Yes i have noticed that i used the mass value as 2 instead of 2.2 sorry
 
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