1. The problem statement, all variables and given/known data In the transformer shown in the figure below, the load resistance RL is 46.0 Ω. The turns ratio N1/N2 is 2.65, and the rms source voltage is ΔVS = 85.0 V. If a voltmeter across the load resistance measures an rms voltage of 27.5 V, what is the source resistance Rs? I've attached an image of the circuit diagram. The answer is 194 Ohms 2. Relevant equations Vprimary/Vsecondary = Isecondary/Iprimary = Nprimary/Nsecondary ΔV=IR 3. The attempt at a solution I've found the current through each loop. Loop 2: VL/RL = 27.5/46 = .5978 Amps Loop 1: I2/I1 = N1/N2............. so, .5978/2.65 = .2256 Amps Here is where I have problems. Can I apply Kirchoff's loop rule to loop 1 (V - Vresistor (=IR) - Vinductor = 0)? And if so, how do I go about finding the potential difference over the large inductor?