Physics120 car collision question

  • Thread starter Thread starter physics120
  • Start date Start date
  • Tags Tags
    Car Collision
AI Thread Summary
The discussion focuses on a physics problem regarding the forces experienced by a person during a car collision, specifically when using seat belts and airbags versus being unrestrained. A 60 kg person in a car traveling at 15 m/s experiences different deceleration forces based on their restraint. The calculations involve determining the net force on the person in both scenarios, emphasizing the importance of crumple zones and the mechanics of deceleration. Participants clarify the correct figures and equations needed for accurate calculations, ultimately leading to a resolution of the problem. The conversation highlights the critical role of safety features in reducing collision forces.
physics120
Messages
34
Reaction score
0

Homework Statement


Seat belts and air bags save lives by reducing the forces exerted on the driver and passengers in an automobile collision. Cars are designed with a "crumple zone" in the front of the car. In the event of an impact, the passenger compartment decelerates over a distance of about 1 meter as the front of the car crumples. An occupant restrained by seat belts and air bags decelerates with the car. By contrast, an unrestrained occupant keeps moving forward with no loss of speed (Newton's first law!) until hitting the dashboard or windshield. These are unyielding surfaces, and the unfortunate occupant then decelerates over a distance of only about 5 mm.
(a) A 60 kg person is in a head-on collision. The car's speed at impact is 15 m/s. Calculate the net force on the person if he or she is wearing a seat belt and the air bag deploys correctly.

(b) Calculate the net force that ultimately stops the person if he or she is not restrained by a seat belt or air bag.

(c) How do these two forces compare to the person's weight?


Homework Equations



F= ma
Vf^2= V0^2 + 2ax
Vf= V0 + at
x= V0*t + .5a(t^2)

The Attempt at a Solution



Well, for (a), what I thought you do is: Force of seatbelt and airbag = mass * acceleration

Then, using Vf^2= V0^2 + 2ax, make Vf = 0. Solve for ax.
So, ax= -(15^2)/(2*1.005) which equals -111.9 m/s^2

Btw, I got 1.005 because the passenger compartment decelerates over 1 m, and the airbag for 0.05mm, so I assumed adding those two nuumbers together, to give me 1.005 m will give me the distance. I am not sure about this, though.

Then, go back to the Force of seatbelt and airbag = mass * acceleration

F= 60 kg * -111.9 m/s^2
=-6716 N


Please help, Thank-you!
 
Last edited:
Physics news on Phys.org
Is the initial speed 17 m/s or 15 m/s?

As to your 5 mm, ignore it. The idea is that if restrained the person won't strike an unyielding surface.

Is the weight 50 kg or 60 as in your calculation?
 
LowlyPion said:
Is the initial speed 17 m/s or 15 m/s?

As to your 5 mm, ignore it. The idea is that if restrained the person won't strike an unyielding surface.

Is the weight 50 kg or 60 as in your calculation?


The initial speed is 15 m/s.

Also, the mass of the person is 60 kg.

Do you happen to know how to do this question? PLease help, if you can.
 
The original statement of the problem says otherwise.
 
LowlyPion said:
The original statement of the problem says otherwise.


I apologize, here is the problem with the correct numbers:


Seat belts and air bags save lives by reducing the forces exerted on the driver and passengers in an automobile collision. Cars are designed with a "crumple zone" in the front of the car. In the event of an impact, the passenger compartment decelerates over a distance of about 1 meter as the front of the car crumples. An occupant restrained by seat belts and air bags decelerates with the car. By contrast, an unrestrained occupant keeps moving forward with no loss of speed (Newton's first law!) until hitting the dashboard or windshield. These are unyielding surfaces, and the unfortunate occupant then decelerates over a distance of only about 5 mm.

(a) A 60 kg person is in a head-on collision. The car's speed at impact is 15 m/s. Calculate the net force on the person if he or she is wearing a seat belt and the air bag deploys correctly.

(b) Estimate the net force that ultimately stops the person if he or she is not restrained by a seat belt or air bag.

(c) How do these two forces compare to the person's weight?
 
NEVERMIND! I completely understand what I was not seeing before. I got the answers for all 3 parts! Thank-you for showing me that I had made an error when I wrote out the numbers in the problem!
 
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Thread 'A cylinder connected to a hanged mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...

Similar threads

Back
Top