Picard Iteration, with a 2nd order ODE

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SUMMARY

The discussion focuses on performing Picard Iterations for the second-order ordinary differential equation (ODE) y'' = 6y^2 with initial conditions y(0) = 0 and y'(0) = -2. The key insight provided is the transformation of the second-order ODE into a first-order ODE by substituting p = y' and pdp/dy = y''. This substitution allows for the application of Picard Iterations effectively, enabling the solution process to proceed. The method emphasizes the importance of back substitution to retrieve the original function y after solving the first-order ODE.

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  • Familiarity with Picard Iteration method
  • Knowledge of first-order and second-order derivatives
  • Basic skills in mathematical substitution techniques
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Homework Statement



Ive been told to perform 2-3 Picard Iterations on the following problem

Homework Equations



y'' = 6y^2

With initial conditions:

y(0) = 0
y'(0)= -2

The Attempt at a Solution



In class we've gone through how to perform picard iterations and it has been easy so far... however this is the first time it has had a second order term at the front. Through internet searches and reading our given notes, I am still not sure how to treat this so I can't really start to try and solve it...

Would anyone be able to give me a nudge in the right direction?Thanks in advance
 
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It's just substitution, i.e f(y, y', y'')-> f(y, p, pdp/dy).
You assume there exists a p: p = y', pdp/dy = y'' and at the end you back substitute for y. This transforms a second order ODE into a first order ODE.
 

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