Pigeonhole Principle: Find Repeating Digits in T={0,1,2}^11

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Let T={0,1,2} so that T^11 represents the set of all strings of eleven digits of T.
a)for every T=T_1T_2...T_11 show that there is a pair T_iT_i+1 of consecutive digits that is repeated using the pigenhole principle.
b)Find a string from T of 10 digits where no repetition exists.
c)Find with justification a postive integer N such that every string of N digits of T contains a repeated triple T_iT_i+1T_i+2.

Answers:
a)Since there are 9 possible pairs and 11 digits one pair will be contained at least once in the string.Is this correct?
b)0011220102.
c)I don't know.How should I proceed?

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AkilMAI said:
Let T={0,1,2} so that T^11 represents the set of all strings of eleven digits of T.
a)for every T=T_1T_2...T_11 show that there is a pair T_iT_i+1 of consecutive digits that is repeated using the pigenhole principle.
b)Find a string from T of 10 digits where no repetition exists.
c)Find with justification a postive integer N such that every string of N digits of T contains a repeated triple T_iT_i+1T_i+2.

Answers:
a)Since there are 9 possible pairs and 11 digits one pair will be contained at least once in the string.Is this correct?
Yeah, that's right.
b)0011220102.
Try again!
c)I don't know.How should I proceed?
Think about why you can write a 10-digit number with no pairs repeating but not an 11-digit number. How would you generalize this to the case of triples?
 
b)2001022112
c)There are 27 different triples
a string of n digist must have n-2 triples in it,we are substracting the last 2 digits.
So 28+2=30 will work.(or I could just look in terms of 27+another triple(3)=30)
 
Good job!
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...

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