Pigeonhole Principle & irrational numbers

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SUMMARY

The discussion focuses on applying the Pigeonhole Principle to demonstrate that for any irrational number x, there exists a positive integer j (where 1 ≤ j ≤ n) such that the absolute value of the difference between jx and the nearest integer to jx is less than 1/n. Participants clarify that the integer n is fixed, and the interval from 0 to 1 can be divided into n equal parts, leading to n distinct values of j. The conclusion emphasizes the unique properties of irrational numbers in this context, differentiating them from rational numbers.

PREREQUISITES
  • Understanding of the Pigeonhole Principle
  • Familiarity with irrational numbers
  • Basic knowledge of real number properties
  • Ability to work with intervals and inequalities
NEXT STEPS
  • Study the Pigeonhole Principle in depth
  • Explore properties of irrational numbers and their implications
  • Learn about real number intervals and their applications
  • Investigate examples of similar mathematical proofs involving irrational numbers
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Mathematics students, educators, and anyone interested in number theory and the properties of irrational numbers will benefit from this discussion.

mndt
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Homework Statement



Let x be an irrational number. Show that the absolute value of the difference between jx and the nearest integer to jx is less than 1/n for some positive integer j not exceeding n.

Homework Equations


The Attempt at a Solution



Ok, I know that it should be solved using pigeonhole Principle

and there is the fact that

for real numbers: 0 <= | jx - [jx] | < 1

specifically for irrational numbers: 0 < | jx - [jx] | < 1

that should make the difference but i can't exactly come up with the correct intervals that form the final conclusion.
 
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I think you are looking at it backwards. It is "n" that is 'given', not j. Given a positive integer, n, divide the interval from 0 to 1 into n equal sized (1/n of course) intervals.
 
HallsofIvy said:
I think you are looking at it backwards. It is "n" that is 'given', not j. Given a positive integer, n, divide the interval from 0 to 1 into n equal sized (1/n of course) intervals.

yes, but considering that 1 <= j <= n we have n different js.

that leaves us with n pigeons (js) and n pigeonholes (intervals). :biggrin: and no useful conclusion.

and why only irrational numbers?!
 

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