1. The problem statement, all variables and given/known data There is a rod of length L pivoted on one end. It is originally at rest horizontally then released. When vertical, an impulse is applied to bring the rod to rest. Throughout the question I have worked out I = 1/3 mL^2 w= √(3g/L) at the vertical position and an impulse of m√(gL/3) is the minimum required to achieve bringing the rod to rest. I am attempting to find the impulse and distance from the pivot so that no horizontal force is exerted at the pivot. 2. Relevant equations G = I dw/dt v=rw a=r dw/dt Angular impulse J = r x (Impulse) = change in angular momentum Angular momentum L = Iw 3. The attempt at a solution I have tried: impulse required = mv = mrw => m√(gL/3) = mr√(3g/L) => r = L/3 I am confused on how to find the impulse and its distance so that the horizontal force on the pivot is 0. Any help is much appreciated. Many thanks.