- #1
fog37
- 1,568
- 108
Hello Everyone,
I have some thoughts about Planck's law. The graph describes the spectral density of electromagnetic radiation emitted by a black body in thermal equilibrium at a given temperature T.
I think the absorption (or absorbance?) spectrum of an ideal blackbody should be a horizontal line to indicate that the body absorbs, at each different wavelength, all in the incident wavelength falling on it, correct?
If a black body is irradiated with purely monochromatic light of any wavelength (sharply peaked spectrum), the blackbody emission spectrum would still looks broadband with its characteristic shape, correct? Why? Why does energy exist at wavelengths that are not present in the incident spectrum?
Assuming an opaque blackbody, i.e. transmittance = 0 and reflectance =0, all the energy that is incident gets absorbed and emitted. In general, it is always true that at, a given wavelength lambda,
emittance(lambda) = absorbance(lambda)
This means that emissivity and absorptivity must be equal at a specific wavelength: what gets absorbed at a certain wavelength should be integrally emitted at that same wavelength. But that does not seem to be the case in most cases. For example, for many materials, the absorption of incident energy occurs at visible wavelengths whereas the emission occurs in the IR so emittance and absorbance can actually be different at the same wavelength...
I have some thoughts about Planck's law. The graph describes the spectral density of electromagnetic radiation emitted by a black body in thermal equilibrium at a given temperature T.
I think the absorption (or absorbance?) spectrum of an ideal blackbody should be a horizontal line to indicate that the body absorbs, at each different wavelength, all in the incident wavelength falling on it, correct?
If a black body is irradiated with purely monochromatic light of any wavelength (sharply peaked spectrum), the blackbody emission spectrum would still looks broadband with its characteristic shape, correct? Why? Why does energy exist at wavelengths that are not present in the incident spectrum?
Assuming an opaque blackbody, i.e. transmittance = 0 and reflectance =0, all the energy that is incident gets absorbed and emitted. In general, it is always true that at, a given wavelength lambda,
emittance(lambda) = absorbance(lambda)
This means that emissivity and absorptivity must be equal at a specific wavelength: what gets absorbed at a certain wavelength should be integrally emitted at that same wavelength. But that does not seem to be the case in most cases. For example, for many materials, the absorption of incident energy occurs at visible wavelengths whereas the emission occurs in the IR so emittance and absorbance can actually be different at the same wavelength...