Yemmy said:
I want to describe a planet that has 13 fifty-two day months and a 36 hour day.
IF someone could point me to a place where I can figure this, it would be appreciated.
What's the math?
It depends. Do want your planet to receive about the same illumination/heating from its star as the Earth gets from the Sun? If so, you are going to need to use a star more Luminous/ massive than our Sun.
At the size range of the Sun, this works out to being a star ~1.5 times the mass of our Sun. This should give you an orbit with the proper length
Yemmy said:
I want to describe a planet that has 13 fifty-two day months and a 36 hour day.
IF someone could point me to a place where I can figure this, it would be appreciated.
What's the math?
As already noted, if you are orbiting a sun-like star, yo are going to get a lot less warming from your star; about 1/4 as much.
You could compensate by orbiting a more luminous star, but that also means a more massive star, which means that in order to maintain the same orbital period, you have to orbit even further out. Luckily luminosity grows at a faster rate than the mass, so this doesn't pose an unsolvable problem.
Thus, if your star had a mass of ~1.5 times that of our Sun, and you orbited at ~2.27 AU, you would get just about the same amount of radiation from the star as we get from the Sun and still have your required orbital period.
Assuming your month is based on the synodic(full moon to full moon) period of the planet's Moon, and the planet was of equal mass to that of the Earth, then it would orbit at ~734,000 km.
You can work this out the following way in case you decide to change your values
Orbital period of planet: 676 days
Synodic period of moon: 52 days
Then the sidereal (fixed star to fixed star) period of the Moon can be found by
T= \frac{1}{\frac{1}{52}+\frac{1}{676}} = 48.29 days
Convert this answer to seconds using a 36 hour day
and plug it into
R =\sqrt[3]{ \frac{T^2GM}{4 \pi^2}}
Where M is the mass of the planet
There is one thing about this solution however. A star of 1.5 solar masses falls in the A spectral class (like Sirius). A class stars radiate more intensely in the ultraviolet range, so, for Earth-like conditions, you are going to need more atmospheric protection.
An alternate solution would be to go with a star somewhat less massive, in the F spectral class, and then, as suggested by rkolter, compensate with Greenhouse effect. This way you don't need as much greenhouse effect nor a star that produces as much in the ultraviolet. You might be able to just get away with increasing the atmosphere thickness somewhat.
Again, this all revolves around how Earth-like you need your planet to be. ( For example, if the air needs to be breathed by humans, then if you increase the atmospheric pressure significantly, you have to decrease the oxygen percentage, in order to maintain a safe partial pressure for the oxygen, as too high a partial pressure cab result in oxygen poisoning.)