Planetary motion and a space station

AI Thread Summary
A space station is positioned in orbit between the Earth and the moon, where the gravitational forces from both bodies are equal. The user initially calculated the distance from Earth as 0.213 but struggled with the final steps of the problem. Clarification was provided regarding the correct interpretation of distances, emphasizing that the radii of the Earth and moon should not be used as distances to the space station. After addressing the confusion, the user indicated they had resolved the issue and sought confirmation on their revised calculations. The discussion concluded with affirmation of the user's solution.
serunder

Homework Statement


A space station is in orbit between the Earth and the moon. The force due to gravity on the space station from the moon is the same as the force due to gravity from the Earth. (FGmoon = FGearth). How far away from the Earth is the space station? How far from the moon is the space station?

Homework Equations

+ attempt at a solution[/B]

a8kkYXK.png


I keep getting 0.213 for r(earth) and I have no idea how to solve for the variable, can someone please help me?
 
Physics news on Phys.org
serunder said:

Homework Statement


A space station is in orbit between the Earth and the moon. The force due to gravity on the space station from the moon is the same as the force due to gravity from the Earth. (FGmoon = FGearth). How far away from the Earth is the space station? How far from the moon is the space station?

Homework Equations

+ attempt at a solution[/B]

View attachment 206637

I keep getting 0.213 for r(earth) and I have no idea how to solve for the variable, can someone please help me?
It (nearly) all made sense until the final step. You had 3.844.108m-rmoon=9.02 rmoon. How did you proceed from there?

The other small mistake is that in your "given" you defined rmoon and rearth as the radii of those two bodies, but thereafter used them as the respective distances from their centres to the space station.
 
haruspex said:
It (nearly) all made sense until the final step. You had 3.844.108m-rmoon=9.02 rmoon. How did you proceed from there?

The other small mistake is that in your "given" you defined rmoon and rearth as the radii of those two bodies, but thereafter used them as the respective distances from their centres to the space station.
I figured it out now I think since like you said, it didn't make sense when I tried to use them as their distance, so what I ended up doing was this:

VOFJuHd.png

sorry for the crappy formatting but does this seem to be correct?
 
serunder said:
I figured it out now I think since like you said, it didn't make sense when I tried to use them as their distance, so what I ended up doing was this:

View attachment 206640
sorry for the crappy formatting but does this seem to be correct?
Yes.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top