PLEASE Can any one solve this problem

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A body dropped from a tower travels half of the total distance in the last second of its motion, prompting a calculation of the total time taken. Using kinematic equations, the distance fallen in time T can be compared to the distance fallen in the last second. The problem simplifies to finding the relationship between the total distance and the distance fallen in the final second. The key is to derive the total time T without needing the actual height of the tower. Ultimately, understanding basic kinematics is essential to solving this problem.
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A body dropped from a tower travels half of the total distance in the last second of its motion
.The total time taken of will be ...?
take g = 10 m/s^2

choices

a) square root 2 secs

b) 2 secs

c) 2+square root 2 secs

d) 2*square root 2 secs
 
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Do you know your basic kinematics formulas?
 
You will need to write down the formula for the distance an object falls under gravity in a time t, in the absence of air resistance. You then need to make a comparison between

the distance 2D that the object falls in T seconds

and

the distance D that the object falls in 1 second .

You do not need to know the actual height of the tower, which we've called 2D, since you will be substituted for D using your second equation. This will give you enough information to solve for T, the total time of the fall. (You'll also find that we don't actually care what value g has...)
 
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