Does ω^2 Equal v^2/r^2 or (v/r)^2 in Angular Velocity Calculations?

  • Thread starter Thread starter acat
  • Start date Start date
  • Tags Tags
    Break
AI Thread Summary
Angular velocity ω is defined as linear velocity v divided by radius r, expressed as ω = v/r. When considering ω squared, both ω^2 = v^2/r^2 and ω^2 = (v/r)^2 are mathematically equivalent. The confusion arises from the interpretation of the equations, but they yield the same result dimensionally. The discussion highlights the importance of clarity in mathematical expressions, especially when solving problems outside of a classroom setting. Understanding these relationships is crucial for tackling related physics problems effectively.
acat
Messages
6
Reaction score
0
ok, if angual velocity ω = linear velocity v / radius r

therefore ω=v/r

but what if i have ω^2 ( to the power of 2 )

does ω^2=v^2/r^2

or does it eqaul ω^2=(v/r)^2

many thanks, this is really bugging me and preventing me solve a problem since I am not in class
 
Mathematics news on Phys.org


it's same. moreover, if you are getting confused check it dimensionally.
 


of course of course, thank you, gawd this is a hard problem I am working on, just making sure all the particulars are in the right place and where they should be as I am not managing to solve this at all, ill carry on though lol. thanks dude
 


acat said:
ok, if angual velocity ω = linear velocity v / radius r

therefore ω=v/r

but what if i have ω^2 ( to the power of 2 )

does ω^2=v^2/r^2

or does it eqaul ω^2=(v/r)^2

many thanks, this is really bugging me and preventing me solve a problem since I am not in class

They are the same.
 


Also this has nothing to do with "Linear and Abstract Algebra" so I am moving it to "General Math".
 
Suppose ,instead of the usual x,y coordinate system with an I basis vector along the x -axis and a corresponding j basis vector along the y-axis we instead have a different pair of basis vectors ,call them e and f along their respective axes. I have seen that this is an important subject in maths My question is what physical applications does such a model apply to? I am asking here because I have devoted quite a lot of time in the past to understanding convectors and the dual...
Insights auto threads is broken atm, so I'm manually creating these for new Insight articles. In Dirac’s Principles of Quantum Mechanics published in 1930 he introduced a “convenient notation” he referred to as a “delta function” which he treated as a continuum analog to the discrete Kronecker delta. The Kronecker delta is simply the indexed components of the identity operator in matrix algebra Source: https://www.physicsforums.com/insights/what-exactly-is-diracs-delta-function/ by...
Back
Top