Yokoko Messages 15 Reaction score 1 Thread starter Oct 26, 2020 #1 Homework Statement I've had a go at these but am unsure about the result. I thought the values would have to be closer to each other. Relevant Equations See picture
mjc123 Science Advisor Homework Helper Messages 1,406 Reaction score 810 Oct 26, 2020 #2 You have not calculated I correctly. I (not √I) = 1/2∑cz2 for ALL ions present. Then you haven't used your calculated value for I in the equation for logγ. You used c. Why? (Do it correctly, and it does come out close to the experimental value.)
You have not calculated I correctly. I (not √I) = 1/2∑cz2 for ALL ions present. Then you haven't used your calculated value for I in the equation for logγ. You used c. Why? (Do it correctly, and it does come out close to the experimental value.)
Yokoko Messages 15 Reaction score 1 Oct 26, 2020 #3 Thanks for your answer. Again, I'm not sure if I understood this correctly. I used c as I thought s = c for simple ions. I now took the root of √I to get I. I assumed the C for KNO3 = 0.0050 and C for CaSO4 = s = 0.0154 This might be where I am wrong? Attachments IMG_20201026_110647.jpg 66.4 KB · Views: 224
Thanks for your answer. Again, I'm not sure if I understood this correctly. I used c as I thought s = c for simple ions. I now took the root of √I to get I. I assumed the C for KNO3 = 0.0050 and C for CaSO4 = s = 0.0154 This might be where I am wrong?
mjc123 Science Advisor Homework Helper Messages 1,406 Reaction score 810 Oct 26, 2020 #4 No! 1/2Σcz2 is I, not √I, as I said before. (What are the units?) I = 0.0666M.
Yokoko Messages 15 Reaction score 1 Oct 26, 2020 #5 Oops thanks, I misread your earlier message. With I = 0.0666 I get an overall value of 0.41 which fits. Thanks again!
Oops thanks, I misread your earlier message. With I = 0.0666 I get an overall value of 0.41 which fits. Thanks again!