Chemistry Please confirm my Activity Coefficient Calculations

AI Thread Summary
The discussion focuses on correcting the calculation of the ionic strength (I) for activity coefficients. The correct formula for I is 1/2∑cz2 for all ions, not √I. The user initially used the concentration (c) instead of the calculated I value in the logγ equation. After clarifying that I equals 0.0666M, the user found that their overall value of 0.41 aligns with experimental results. This highlights the importance of accurately calculating ionic strength for reliable activity coefficient results.
Yokoko
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I've had a go at these but am unsure about the result. I thought the values would have to be closer to each other.
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IMG_20201025_192654__01.jpg
 
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You have not calculated I correctly. I (not √I) = 1/2∑cz2 for ALL ions present.
Then you haven't used your calculated value for I in the equation for logγ. You used c. Why?
(Do it correctly, and it does come out close to the experimental value.)
 
IMG_20201026_110941.jpg

Thanks for your answer. Again, I'm not sure if I understood this correctly.

I used c as I thought s = c for simple ions. I now took the root of √I to get I.

I assumed the C for KNO3 = 0.0050 and C for CaSO4 = s = 0.0154

This might be where I am wrong?
 

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No! 1/2Σcz2 is I, not √I, as I said before. (What are the units?) I = 0.0666M.
 
Oops thanks, I misread your earlier message.
With I = 0.0666 I get an overall value of 0.41 which fits.

Thanks again!
 
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