- #1

munna007

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i m trying to solve this question by method given in most of the standard books i.e.

Vc(t) = Vc([itex]\infty[/itex]) - [Vc(0[itex]\hat{}[/itex]-) - Vc([itex]\infty[/itex]) ] e [itex]\hat{}[/itex] -t/RC

first i found Vc(0[itex]\hat{}[/itex]-) by considering switch open and inductor behaving like short and capacitor open at steady state...then i find voltage acroos 4 ohm resistor i.e.

V4 = (4 * 18)/6 = 12 volt

now = Vc(0[itex]\hat{}[/itex]-) = [C(total)/2c ] * V4 = 4 volt

now i m finding Vc([itex]\infty[/itex]) by considering switch closed ...and at steady state inductor will be shorted and both capacitors will be opened...and now inductor path and capacitor c bot are in parallel and i have confused what to do here next ...please help me...

Vc(t) = Vc([itex]\infty[/itex]) - [Vc(0[itex]\hat{}[/itex]-) - Vc([itex]\infty[/itex]) ] e [itex]\hat{}[/itex] -t/RC

first i found Vc(0[itex]\hat{}[/itex]-) by considering switch open and inductor behaving like short and capacitor open at steady state...then i find voltage acroos 4 ohm resistor i.e.

V4 = (4 * 18)/6 = 12 volt

now = Vc(0[itex]\hat{}[/itex]-) = [C(total)/2c ] * V4 = 4 volt

now i m finding Vc([itex]\infty[/itex]) by considering switch closed ...and at steady state inductor will be shorted and both capacitors will be opened...and now inductor path and capacitor c bot are in parallel and i have confused what to do here next ...please help me...

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