#### vijayramakrishnan

1. Homework Statement
cos(θ)^x+sin(θ)^x=1
find the number of real values of x satisfying this equation

2. Homework Equations
none

3. The Attempt at a Solution
the answer given is 1 which is 2.which is obvious but i don't know how to prove that it is the only solution available

Last edited by a moderator:
Related Precalculus Mathematics Homework Help News on Phys.org

#### Nathanael

Homework Helper
but i don't know how to prove that it is the only solution available
You want to prove there is no x, other than 2, which gives equality for all values of θ.

Choose any particular θ and show that the only x-value for that particular θ which gives equality is x=2 (that would prove it, right?)

What particular value of θ might it be easy to show this for?

#### vijayramakrishnan

You want to prove there is no x, other than 2, which gives equality for all values of θ.

Choose any particular θ and show that the only x-value for that particular θ which gives equality is x=2 (that would prove it, right?)

What particular value of θ might it be easy to show this for?
thank you for replying sir,i want to prove that 2 is the only solution possible.

#### Nathanael

Homework Helper
thank you for replying sir,i want to prove that 2 is the only solution possible.
When you say "the only solution possible," what you really mean is, "the only solution possible for all values of θ" right?

If you were to choose a particular value of θ and prove that 2 is the only solution for that θ, then that would prove what you want, because if x is not 2 then x does not solve it for that particular θ you chose.
This means you only have to prove it for any single value of θ. Do you agree?

I didn't want to hint at it too much, but if you choose the θ such that cosθ=sinθ then you can factor together the exponent x and complete the proof.

#### vijayramakrishnan

When you say "the only solution possible," what you really mean is, "the only solution possible for all values of θ" right?

If you were to choose a particular value of θ and prove that 2 is the only solution for that θ, then that would prove what you want, because if x is not 2 then x does not solve it for that particular θ you chose.
This means you only have to prove it for any single value of θ. Do you agree?

I didn't want to hint at it too much, but if you choose the θ such that cosθ=sinθ then you can factor together the exponent x and complete the proof.
thank you sir, from there i will try on my own