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Abhishekdas
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Please help me with this Question based on angular momentum...
A uniform rod of length L rests on a frictionless horizontal surface.The rod is pivoted about a fixed frictionless axis at one end.Initially at rest the rod is hit by a bullet traveling parallel to the horizontal surface and perpendicular to the rod with speed v.It hits the rod at the centre and becomes embedded in it.
Mass of rod = 6m
mass of bullet = m
Find the final angular velocity of the rod...?
Impulse*r=Change in angular momentum.
angular momentum abt a point =I*w
I went about by considering the axis as my reference n used d above eqn..
mass of body after impact = 7m..
So, MI of the body about axis = 7mL2/3
my eqn is
mvL/2=(7mL^2*w)/3
I am getting w=3v/14L
ans in buk is 2v/9L...
Thank you...
Homework Statement
A uniform rod of length L rests on a frictionless horizontal surface.The rod is pivoted about a fixed frictionless axis at one end.Initially at rest the rod is hit by a bullet traveling parallel to the horizontal surface and perpendicular to the rod with speed v.It hits the rod at the centre and becomes embedded in it.
Mass of rod = 6m
mass of bullet = m
Find the final angular velocity of the rod...?
Homework Equations
Impulse*r=Change in angular momentum.
angular momentum abt a point =I*w
The Attempt at a Solution
I went about by considering the axis as my reference n used d above eqn..
mass of body after impact = 7m..
So, MI of the body about axis = 7mL2/3
my eqn is
mvL/2=(7mL^2*w)/3
I am getting w=3v/14L
ans in buk is 2v/9L...
Thank you...