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Hello,

I REALLY need help deriving a function

if [tex]f(x) = \frac{-x-2}{(x-2)^3}[/tex]

what would its derivative be???

Here's what I did so far::

Using the quotient rule,

[tex]f'(x) = \frac{(x-2)^3(-1) - (-x-2)(3(x-2)^2(1))}{((x-2)^3)^2)}[/tex]

[tex]= \frac{-(x-2)^3 + (x+2)(3(x^2-4x+4))}{(x-2)^6}[/tex]

[tex]= \frac{-(x^2 -4x+4)(x-2) + (x+2)(3x^2 -12x +12)}{(x-2)^6}[/tex]

[tex]= \frac{-(x^3 -4x^2 + 4x -2x^2 +8x -8) + (3x^3 -12x^2 + 12x +6x^2 -24x +24)}{(x-2)^6}[/tex]

[tex]= \frac{-x^3 + 4x^2 -2x + 2x^2 -8x + 8 + 3x^3 - 12x^2 + 12x + 6x^2 -24x +24}{(x-2)^6}[/tex]

[tex]f'(x) = \frac{2x^3 - 24x + 32}{(x-2)^6}[/tex]

Is this the derivative, and if so, how can I find the critical numbers? (When the derivative equals 0 or DNE(does not exist))

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# Please Help Me

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