Two obvious solution of the homogeneous part of the equation are y=x and y=x². The third is a special function.
Nevertheless, particular solutions for the whole ODE can be derived :
Let y=x*f(x) and solve the ODE which unknown is f(x).
#3
artan
7
0
I can find that first and second obvious solution of the homogeneous part x and x^2,but how can I find the third,it is something of x^x.
Can anyone explain how to find the particular solution showing me some steps of the solution.Thank you
#4
artan
7
0
Can you write the special function and show me some steps how to find particular solution.Thank you
I started solving this DE this way:
y=x^m
y'=m*x^(m-1)
y''=m(m-1)x^(m-2)
y'''=m(m-1)(m-2)x^(m-3)
and replace them in DE we get:
(m-1)(m-2)(m*x^(m-1)-x^m)=0
so we get :
y1=x
y2=x^2
m*x^(m-1)-x^m=0 this is the third solution but i don't know how to find it
thank you.
#8
JJacquelin
801
35
artan said:
I started solving this DE this way:
y=x^m
You suppose that the third solution is on the patern y=x^m which is not the case. As a consequence this method cannot lead to the third solution.
By chance, the first and the second solution are on the patern y=x^m, so leading to m=1 and m=2. But obviously not the third.
#9
artan
7
0
MR.Kosovtsov can you write the whole method how did you get the solution,not just the final solution.
I will be grateful.
Thank you.
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#10
artan
7
0
which method should i use to get the solution.
Can you write for me the beginig of the method you use?
I will be grateful.
Thank you for the help.
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#11
JJacquelin
801
35
Hi !
In attachment, the solution for the homogeneous ODE.
Same method for the complete ODE.