Please if anyone can help me to solve this differential equation.

artan
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Please if anyone can help me to solve this differential equation.
 
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Hello,

Two obvious solution of the homogeneous part of the equation are y=x and y=x². The third is a special function.
Nevertheless, particular solutions for the whole ODE can be derived :
Let y=x*f(x) and solve the ODE which unknown is f(x).
 


I can find that first and second obvious solution of the homogeneous part x and x^2,but how can I find the third,it is something of x^x.


Can anyone explain how to find the particular solution showing me some steps of the solution.Thank you
 


Can you write the special function and show me some steps how to find particular solution.Thank you
 


The general solution to your ODE is as follows

y(x) = -3x(x-3)\ln(x)+[(-\frac{1}{2}x^2+x)\int_{-x}^∞ \frac{\exp(-t)}{t}dt -\frac{1}{2}\exp(x)(x-1)]C_1-\frac{x^3+9}{2}+x^2C_2+xC_3

where C_i are arbitrary constants.
 


I started solving this DE this way:
y=x^m
y'=m*x^(m-1)
y''=m(m-1)x^(m-2)
y'''=m(m-1)(m-2)x^(m-3)

and replace them in DE we get:

(m-1)(m-2)(m*x^(m-1)-x^m)=0
so we get :
y1=x
y2=x^2
m*x^(m-1)-x^m=0 this is the third solution but i don't know how to find it
thank you.
 


artan said:
I started solving this DE this way:
y=x^m

You suppose that the third solution is on the patern y=x^m which is not the case. As a consequence this method cannot lead to the third solution.
By chance, the first and the second solution are on the patern y=x^m, so leading to m=1 and m=2. But obviously not the third.
 


MR.Kosovtsov can you write the whole method how did you get the solution,not just the final solution.
I will be grateful.
Thank you.
 
Last edited:
  • #10


which method should i use to get the solution.
Can you write for me the beginig of the method you use?
I will be grateful.
Thank you for the help.
 
Last edited:
  • #11


Hi !

In attachment, the solution for the homogeneous ODE.
Same method for the complete ODE.
 

Attachments

  • Homogeneous ODE.JPG
    Homogeneous ODE.JPG
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  • #12


Thank you for the help
 
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