Please prove or disapprove this equality

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The equality in question, sum_(n in Z)e^(2 pi i n s) = 2 delta(s), is debated, with some arguing it is false. The right-hand side should instead be represented as sum_{n in Z} delta(s-n), based on Fourier series principles. The discussion highlights that the sum does not converge, as the limit of e^(2 pi i n s) does not approach zero as n approaches infinity. Participants emphasize the need to analyze the Fourier series expansion of the function with a period of one. The conclusion suggests that the original equality does not hold true.
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Please help me prove or disapprove the following equality:

sum_(n in Z)e^(2 pi i n s) = 2 delta (s)

Z is the set of integers and s any variable and delta is the usual delta function that is 0 when s is different from 0 and infinite if s is 0.

Thanks
 
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I think it's false.

Based on Fourier series I think the RHS of that equality should, [instead of 2 delta(s)], read:

\sum_{n\,\, \mbox{\rm in Z}} \delta(s-n)

Hint : Consider the Fourier series expansion of the above (period=1) function of s.
 
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By what you wrote above did you mean

\sum^{\infty}_{n=-\infty} e^{2 \pi i n s}

This sum doesn't converge because lim_{n\rightarrow\infty}e^{2 \pi i n s}\neq0
 
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