Plot the lines of the electric field between a small point charge

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SUMMARY

The discussion focuses on calculating the electric field (E) and potential (V) inside and outside an infinite plate capacitor. Inside the capacitor, the electric field is defined as E = σ / ε₀, leading to a potential V = Ed. Outside the capacitor, both E and V are zero. Additionally, the conversation addresses plotting electric field lines between a small positive point charge and a large negatively charged plate, emphasizing the need to consider superposition by first analyzing the field lines from each charge separately before combining them.

PREREQUISITES
  • Understanding of electric field concepts, specifically for infinite charged plates.
  • Familiarity with potential energy in electrostatics.
  • Knowledge of superposition principle in electric fields.
  • Proficiency in using polar coordinates for integration in physics problems.
NEXT STEPS
  • Study the electric field due to an infinite charged plate in detail.
  • Learn about the superposition principle in electrostatics.
  • Explore integration techniques in polar coordinates for electric field calculations.
  • Investigate graphical methods for plotting electric field lines between point charges and plates.
USEFUL FOR

This discussion is beneficial for physics students, electrical engineers, and educators focusing on electrostatics, particularly those interested in electric field calculations and visualizations.

galipop
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I've been asked to complete electric field E and potential V inside and outside of a simple plate capacitor (the plates are infinitely large and the distance between the two plates is d.)

My working is as follows.

Inside the cap-
E = \frac{ \sigma } { \epsilon_{o} }

then potential V=Ed

Outside the cap
E=0
V=0

does this seem to cover the question, or am I missing something?

Also I need to plot the lines of the electric field between a small point charge (+) and a large metal plate (charge -)...
for this I'm guessing the lines of the charge leave the charge going straight to the plate, correct?
 
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I can't see your LaTeX (there's a temporary problem with displaying LaTeX), but for the first part, your result is essentially correct. But the way to go about it would be to start with the electric field due to an infinite charged plate (sheet, wall, whatever).

For (2), your answer is incorrect. This is essentially a superposition problem. First draw the field lines for a single charge. Then draw them for a charged plate. Now combine the two.
 
Thanks for the reply!

Can you expand a bit more on starting with an electric field due to an infinite charged plate?
 
anyone? .
 
Imagine a point charge, q, at height l above the plane that has charge density δ. Take the point directly beneath the point charge as the origin of a polar coordinate system. Use polar coordinates since all points on a circle of radius r will have the same force on q: Their horizontal components cancel and their vertical components add. Taking a ring of radius r and width dr, the total area is 2π rdr so the charge is 2πδr dr. The straight line distance from q to a point on that circle is L= √(l2+ r2) so the vertical component of the total force from that ring is (2qπδ/L2)(l/L)= 2qπδl/L3. Integrate that with respect to r (don't forget that L is not a constant- it depends on r) from r= 0 to r= infinity.
 

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