Plot the space-time diagram of a photon and a spaceship

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In the discussion about plotting a space-time diagram for a photon and a spaceship, the spacecraft is represented as a red point, while the photon is incorrectly depicted as a green point instead of a line. The natural zero point for the diagram is where the spacecraft meets Earth, synchronizing their clocks. Event A is identified as the photon, which should be represented by its light cone due to its speed. The emission and arrival of the photon at Earth are distinct events that should be shown as separate points connected by a line. The context suggests that the photon is emitted when the spacecraft reaches Titan, indicating the importance of this event in the diagram.
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Homework Statement
An inertial observer O ' in a spacecraft, moving with four-speed U = 2 (c, u) seen by a
Earth observer O, passes by Earth and synchronizes his clock with O's clock. This
observer turns to Titan, a moon of Saturn that is (at that time) at a distance
Δx = 1.2 billion km from Earth. The ship throws a pulse of light towards the Earth, with four-moment p' = (E'/c)(1,-1,0,0)
Relevant Equations
I think we don't need any.
Be the red point this spacecraft , the purple line the world line with slope = 2 and the green point a photon thrown towards the Earth from the spacecraft , would this spacetime diagram ok? (distance would be 1.2 billion km, and the time, 1000 times of shown, but scale is badly displayed, even the red point wouldn't be at that position, but I did it like this just for showing it).

2020-05-11.png
 
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What is event A?

The photon travels through spacetime, it should be a line not a dot.

The natural zero for this diagram would be the meeting of spacecraft and Earth. That's where the clocks are synchronized.
 
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event A is the photon, because it has the light cone as world lines because of its speed v=c.
It is plotted as the green point, though it should be a line. That's what I don't grasp, because if photon arrives at the Earth in a certain moment, it should be a point. Nevertheless, I don't know the distance it travels.
 
The photon is not an event. The emission and arrival at Earth are events. They are points that should appear as separate points in the diagram, connected by a line.
pepediaz said:
Nevertheless, I don't know the distance it travels.
The problem statement tells you, assuming the photon is emitted when the spacecraft reaches Titan (otherwise: why would they tell us about Titan).
 
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The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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