- #1
heman
- 361
- 0
hi,i want to know the command which i have to give to plot this using mathematica.actually interval should be sufficient and near by origin.thx in advance.
z^2-xy+1=0
z^2-xy+1=0
To plot this equation in Mathematica, you can use the Plot3D function with the equation as the first argument and the variables (x, y) as the second argument. This will generate a three-dimensional plot of the equation in the (x, y, z) coordinate system.
You can specify an interval around the origin by using the PlotRange option in the Plot3D function. For example, Plot3D[z^2-xy+1=0, {x,-1,1}, {y,-1,1}, PlotRange->{-1,1,-1,1}] will plot the equation within the interval [-1,1] for both the x and y axes.
Yes, you can change the color of the plot by using the ColorFunction option in the Plot3D function. You can choose from a variety of built-in color functions or create your own custom color function.
You can add labels and a title to the plot by using the LabelStyle and PlotLabel options in the Plot3D function. For example, Plot3D[z^2-xy+1=0, {x,-1,1}, {y,-1,1}, LabelStyle->Directive[Black, Bold], PlotLabel->"Plot of z^2-xy+1=0"] will add a bold, black label and a title to the plot.
Yes, you can rotate the plot by using the ViewPoint option in the Plot3D function. This option allows you to specify the point from which the plot is viewed. You can also use the ViewVertical option to change the orientation of the plot.