Plotting the graph of pendulum period versus length

Click For Summary
SUMMARY

The discussion focuses on the mathematical relationship between the period of a pendulum (T) and its length (l), specifically addressing why T is squared in the formula T=2∏√(l/g). Squaring T simplifies the analysis by allowing a linear relationship when plotting T² against l, resulting in a straight line with a gradient of 4∏²/g. This transformation facilitates easier interpretation of data, as linear graphs are simpler to analyze than curves. The necessity of squaring T is primarily for convenience in identifying relationships between variables.

PREREQUISITES
  • Understanding of pendulum mechanics and dynamics
  • Familiarity with the formula T=2∏√(l/g)
  • Basic knowledge of graphing techniques and linear relationships
  • Ability to interpret mathematical transformations
NEXT STEPS
  • Explore the derivation of the pendulum period formula T=2∏√(l/g)
  • Learn about linear regression techniques for analyzing experimental data
  • Investigate the effects of varying gravitational acceleration on pendulum motion
  • Study the principles of dimensional analysis in physics
USEFUL FOR

Students of physics, educators teaching mechanics, and anyone interested in understanding the mathematical relationships in pendulum motion.

Revin
Messages
3
Reaction score
0
why do we square the value of T ( time period) while plotting the graph of effect on time period of a pendulum with change in its effective length ?

also while deriving the formula of
T=2∏√(l/g)

why do we take T^2 = 1/g.

Whats the need for squaring the time period ?
 
Physics news on Phys.org
Because for the convenience. even if you don't square Timeperiod nothing will change, you will always get a parabola with T>0 and l>0
 
To get a straight-line graph, you can plot either T2 versus l, or T versus √l. If your calculator doesn't have a square-root key, the first method is easier.
 
More generally if you are trying to identify the relationship between two quantities it is difficult to look at a curve and say it is an arc of a circle, parabola, hyperbola, exponential or whatever. However it is much easier to recognise a straight line. So we transform the equation to produce a linear relationship. In this case squaring the equation gives a straight line by plotting t2 against l.
This gives a straight line whose gradient would be is 4∏2/g.
 

Similar threads

  • · Replies 13 ·
Replies
13
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 2 ·
Replies
2
Views
15K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 14 ·
Replies
14
Views
2K
  • · Replies 36 ·
2
Replies
36
Views
4K
  • · Replies 21 ·
Replies
21
Views
4K
  • · Replies 3 ·
Replies
3
Views
3K