Polar coordinates of an electric field

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Homework Help Overview

The problem involves calculating the direction of the electric field generated by three point charges using polar coordinates. The charges are specified with their magnitudes and signs, and the setup includes a diagram for reference.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss the calculations of the electric field components and the resulting angle. There is a mention of an incorrect angle derived from the calculations, prompting questions about the setup and the location of interest.

Discussion Status

Some participants have offered suggestions to review the signs of the components involved in the calculations. The discussion is ongoing, with attempts to clarify the setup and ensure accurate calculations.

Contextual Notes

There is a specific focus on the polar coordinate system and the range of angles being considered. The original poster's calculations are noted to be potentially flawed, leading to further inquiry about the assumptions made in the problem setup.

netteo
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Homework Statement



Three charges are arranged as presented below. Q1= 5.00E-9C, Q2= 6.00E-9C and Q3= -7.00E-9C.

http://img15.imageshack.us/img15/9250/physicskf.png

D) Find the direction of the above electric field using the polar coordinate system 0°< θ <360°

Homework Equations



tan θ = o/a

The Attempt at a Solution



I found my

E1 = 500
E2 = 5400
E3 = -700

Ex = 500 cos 18.4° + (-700) = -225.6
Ey = 500 sin 18.4° + 5400 = 5557.8

But the angle that I got was incorrect which was 24.63°.

Help anyone?
 
Last edited by a moderator:
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netteo said:

Homework Statement



Three charges are arranged as presented below. Q1= 5.00E-9C, Q2= 6.00E-9C and Q3= -7.00E-9C.

http://img15.imageshack.us/img15/9250/physicskf.png

D) Find the direction of the above electric field using the polar coordinate system 0°< θ <360°

Homework Equations



tan θ = o/a

The Attempt at a Solution



I found my

E1 = 500
E2 = 5400
E3 = -700

Ex = 500 cos 18.4° + (-700) = -225.6
Ey = 500 sin 18.4° + 5400 = 5557.8

But the angle that I got was incorrect which was 24.63°.

Help anyone?
You are finding the Electris Field at what location?
 
Last edited by a moderator:
Oops, sorry about that. Point P (0.3m,-0.1m)
 
Review the signs of your components .
 

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