Polar graphs really important and tangents

Click For Summary
SUMMARY

The discussion focuses on finding points on the cardioid defined by the polar equation r = a(1 + cos(θ)) where the tangents are perpendicular to the initial line. The solution involves solving the derivative dx/dθ = 0, which leads to identifying critical points. The absence of π in the solution is clarified by noting that when finding tangents parallel to the initial line, π is included due to the behavior of dy/dθ. The key takeaway is the relationship between the derivatives and the conditions for perpendicularity in polar coordinates.

PREREQUISITES
  • Understanding of polar coordinates and equations
  • Knowledge of derivatives in calculus
  • Familiarity with the cardioid shape and its properties
  • Ability to solve parametric equations
NEXT STEPS
  • Study the properties of polar curves, specifically cardioids
  • Learn how to compute derivatives in polar coordinates
  • Explore the concept of tangents in polar graphs
  • Investigate the relationship between parametric equations and their derivatives
USEFUL FOR

Students preparing for exams in calculus, mathematicians interested in polar coordinates, and educators teaching advanced mathematics concepts.

phospho
Messages
250
Reaction score
0
Hi, I really need help with this as exam is tomorrow

The question is to find the points on the cardioid r=a(1+costheta) where the tangents are perpendicular to the initial line

here is the answer

http://gyazo.com/e8b4cbd36f0ef71d0cdf13be256d8618

Why is pi not included in the solution, while if I was finding parallel to the initial line then pi would be included.

please help
 
Physics news on Phys.org
hi phospho! :smile:
phospho said:
Why is pi not included in the solution, while if I was finding parallel to the initial line then pi would be included.

you're solving dx/dθ = 0

but you're using an x,y graph, so you really need to solve dx/dy = 0

ie dx/dθ / dy/dθ = 0

the solutions to this are the same as the solutions to dx/dθ = 0, except if dy/dθ = 0 (which it is for θ = π) :wink:
 

Similar threads

Replies
1
Views
4K
Replies
5
Views
2K
Replies
2
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 3 ·
Replies
3
Views
1K
Replies
3
Views
2K
Replies
2
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 20 ·
Replies
20
Views
4K