Polarization of light and sunglasses

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    Light Polarization
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Light from the sun is unpolarized, meaning its electromagnetic fields oscillate randomly. Polarization occurs when light waves vibrate in a specific plane, but this does not imply that one of the fields is eliminated; both electric and magnetic fields coexist. When light hits a water surface, some rays become polarized parallel to that surface, but not all. Sunglasses designed to filter vertically polarized light would not block all light, as only a portion of the waves is polarized horizontally. At Brewster's Angle, reflected light achieves perfect polarization, but at other angles, both horizontal and vertical components remain present.
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Light coming from the sun is unpolarised therefore the electromagnetic field is moving randomly along the direction of propagation .

When light is polarised this means that the photons vibrate in one plane , but how can this happen ? it means that either one of the electric or magnetic fields must be cut out , is that right ?

When light strikes a water surface then some rays will be polarized parallel to the surface but then if sunglasses were made of material that only let's light in vertically then we should see nothing ?!
 
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Polarized light does not consist of photons vibrating in a plane. The electromagnetic wave itself is polarized. Neither of the fields are cut out, both exist.

When light strikes a water surface then some rays will be polarized parallel to the surface but then if sunglasses were made of material that only let's light in vertically then we should see nothing ?!

Only some of the waves are. The rest are not polarized horizontally.
 
ZxcvbnM2000 said:
Light coming from the sun is unpolarised therefore the electromagnetic field is moving randomly along the direction of propagation .
Perpendicular to direction of propagation.

ZxcvbnM2000 said:
When light strikes a water surface then some rays will be polarized parallel to the surface but then if sunglasses were made of material that only let's light in vertically then we should see nothing ?!
Only at Brewster's Angle does reflected light become perfectly polarized. At any other angle, you still have both the horizontal and vertical components remaining. The vertical component simply happens to be attenuated.
 
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