Koala Bear Population Limits and Growth: A Mathematical Analysis

  • Thread starter Thread starter Jan Hill
  • Start date Start date
  • Tags Tags
    Limits population
Jan Hill
Messages
63
Reaction score
0

Homework Statement


The population of koala bears within a nature reserve at time t is greater than or equal to 0 is given by the function
N(t) = 200t/4 + t

Determine a)the lim as t-->infinity (the limiting population size)

b)when the population is exactly half of its limiting size


Homework Equations





The Attempt at a Solution


I don't really know where to start
 
Physics news on Phys.org
I assume you mean N(t)= 200t/(4+ t). What you wrote does not have a limiting value.

To find the limit, divide both numerator and denominator by t:
N(t)= 200/(4/t+ 1). Now, as t goes to "infinity" (as t gets large), that "4/t" goes to 0 and what remains is the limit.

Now that you know that limiting size,set 200t/(4+ t) equal to half that number and solve for t.
 
Thank you
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
Back
Top