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Well, you have a quadratic expression in P: {P}({\frac{P}{g}-1}) = P^2/g - P. That's solvable, but kinda messy, so-o-o-o...
... before we go solving for P, I recommend confirming whether it satisfies the differential equation first. (If it doesn't, then there's no need to spend time on solving for P
) So, implicit differentiation and c e^{rt} = {P}({\frac{P}{g}-1}) ...
... before we go solving for P, I recommend confirming whether it satisfies the differential equation first. (If it doesn't, then there's no need to spend time on solving for P
