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Position and acceleration graphs
- Thread starter dlee9
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- Acceleration Graphs Position
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To determine position and acceleration graphs from given velocity graphs, it's essential to understand that acceleration is represented by the slope of the velocity graph. The acceleration graph cannot be option F, as it does not show any abrupt changes in slope. Additionally, the position graph cannot be option I, since a negative slope at t=7 indicates that the velocity should also be negative. Correctly identifying these relationships is crucial for accurate graph interpretation. Understanding these concepts will help clarify the connections between the different types of motion graphs.
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CWatters
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I think you should check the first and last answers..
The graph for ax cannot be F. Acceleration is the slope of the velocity curve. At no point does the slope of the velocity curve change abruptly.
The graph for the position x cannot be I. At t=7 the slope of the position graph I is negative so the velocity should be negative.
The graph for ax cannot be F. Acceleration is the slope of the velocity curve. At no point does the slope of the velocity curve change abruptly.
The graph for the position x cannot be I. At t=7 the slope of the position graph I is negative so the velocity should be negative.
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19.
For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Let's declare that for the cylinder,
mass = M = 10 kg
Radius = R = 4 m
For the wall and the floor,
Friction coeff = ##\mu## = 0.5
For the hanging mass,
mass = m = 11 kg
First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on.
Force on the hanging mass
$$mg - T = ma$$
Force(Cylinder) on y
$$N_f + f_w - Mg = 0$$
Force(Cylinder) on x
$$T + f_f - N_w = Ma$$
There's also...
This problem is two parts. The first is to determine what effects are being provided by each of the elements - 1) the window panes; 2) the asphalt surface. My answer to that is
The second part of the problem is exactly why you get this affect.
And one more spoiler:
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