- #1
bigzee20
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Homework Statement
An automobile and train move together along
parallel paths at 38.9 m/s.
The automobile then undergoes a uniform
acceleration of −4 m/s2 because of a red light
and comes to rest. It remains at rest for 71.7 s,
then accelerates back to a speed of 38.9 m/s
at a rate of 3.52 m/s2.
How far behind the train is the automobile
when it reaches the speed of 38.9 m/s, as-
suming that the train speed has remained at
38.9 m/s? Answer in units of m.
Ok i know that the total distance that the train covered in those 71.7s is 2789.13m now what else do i need to do to find out how far behind is the automobile? How can i tell the total distance traveled by the car? is it d = vi(t)+1/2a(t)^2?
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