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## Homework Statement

The position of a particle as a function of time (in s) is given by C

_{1}+ C

_{2}t + C

_{3}t

^{2}.

Let C

_{1}= 19.0 m, C

_{2}= 39.1 m/s, and C

_{3}= -0.62 m/s

^{2}.

(a) What is the velocity of the particle at time t = 13.0 s?

(b) What is the particle's acceleration at time t = 13.0 s?

## Homework Equations

C

_{1}+ C

_{2}t + C

_{3}t

^{2}.

Let C

_{1}= 19.0 m, C

_{2}= 39.1 m/s, and C

_{3}= -0.62 m/s

^{2}.

## The Attempt at a Solution

I wasn't sure how to do this problem from the beginning, so I tried playing around with some numbers to see if anything could come up. I tried substituting 13.0 into the formula to create a quadratic equation and got: -104.78x

^{2}+ 508.3x + 19. I then used the quadratic formula to get some points: (-0.037, 0.0495) (4.888, 0.06186). If I'm doing anything right so far, I would say from the graph that the velocity is decreasing and the acceleration is negative?

Any help would be greatly appreciated. Thank you.