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The author is defining the point at which the object is dropped as x = 0, and the point on the ground as x = 100.foo9008 said:Homework Statement
for part b , why when t = 0 , x= 0 , why not x =100 ? the author gave that the object drop from height of 100ft at the start of the question.
Homework Equations
The Attempt at a Solution
Is it wrong to consider x=100 when t=0??Mark44 said:The author is defining the point at which the object is dropped as x = 0, and the point on the ground as x = 100.
Yes, if you're trying to follow the author's work.foo9008 said:Is it wrong to consider x=100 when t=0??
The initial position of the object when it is dropped from 100 ft is 0 ft.
It takes approximately 4.5 seconds for the object to reach the ground.
The equation used to calculate the position of the object at any given time is x = -16t^2 + 100, where t is the time in seconds and x is the position in feet.
Yes, air resistance does affect the position of the object. However, for objects dropped from a height of 100 ft, the effect of air resistance is usually negligible.
The position of the object at a specific time can be determined by plugging in the time value into the equation x = -16t^2 + 100 and solving for x, which represents the position in feet.