Possibilities: 15 t/f, one unanswered

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A test with 15 true/false questions allows for 2^15 (32,768) ways to answer if all questions are answered. If one question is left unanswered, the correct calculation is 15*(2^14), resulting in 245,760 ways to mark the paper. The initial incorrect approach mistakenly multiplied by 3 instead of recognizing the selection of one unanswered question. A tree diagram was also corrected to reflect the proper pattern of choices. Understanding the multiplication of choices is key to solving these types of problems effectively.
mishima
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Homework Statement


If a test consists of 15 true false questions, in how many ways can a student mark his paper if:
a) he answers each question
b) he leaves anyone question unanswered.


Homework Equations


Multiplication of choices


The Attempt at a Solution


a) 2^15 Correct.
b) 3*(2^14) Incorrect. (right answer = 245,760)
One question has 3 choices, the rest have 2?
 
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Also made a tree diagram up to question 4, showing the pattern 3, 8, 20, 48.
 
mishima said:

Homework Statement


If a test consists of 15 true false questions, in how many ways can a student mark his paper if:
a) he answers each question
b) he leaves anyone question unanswered.


Homework Equations


Multiplication of choices


The Attempt at a Solution


a) 2^15 Correct.
b) 3*(2^14) Incorrect. (right answer = 245,760)
One question has 3 choices, the rest have 2?

Don't forget you have 15 choices for which question to not answer.
 
Ah, okay so it's as if you make one selection out of 15, then you have 14 to pick 2 from...so

15*(2^14)

Thank you.
 
My tree diagram was also set up incorrectly, correct sequence would be 1, 4, 12, 24 for up to 4 questions.
 
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