Potential barrier, reflection coefficient

AI Thread Summary
Electrons with 100 eV kinetic energy enter a grounded metal tube A and then move to tube B, which is at -50V. The potential barrier is considered discontinuous, and the reflection coefficient is calculated using the wave numbers derived from the energy and potential. The reflection coefficient formula is applied, assuming the potential barrier V0 is 50 eV, leading to an estimated reflection coefficient of approximately 0.3. The discussion emphasizes the importance of converting potential differences into potential energy and confirms that potential energy is calculated as qV. Understanding these concepts is crucial for solving the problem accurately.
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Homework Statement


Electrons are pushed into a grounded metal tube A by the kinetic energy of 100 eV. After having gone through the tube it passes into another tube, B, at some distance from A. Tube B is kept at a potential of -50V. Calculate how many of the electrons are reflected back into the tube A. ( Assume the potential barrier is discontinuous)

Homework Equations


If ##E>V_0## for our barrier then we have the wave numbers
##k_1 = \sqrt{\frac{2mE}{\hbar^2}}## for ##x<0## and
##k_2 = \sqrt{\frac{2m[E-V_0]}{\hbar^2}}##
for the wave functions
##\Psi_1 = Ae^{ik_1x}+Be^{-ik_1x}## for ##x < 0## and
##\Psi_2 = Ce^{ik_2x}## for ##x>0##.

The reflection coefficient is then
##R = \left(\frac{k_1-k_2}{k_1+k_2}\right)^2##.

The Attempt at a Solution


I have an electric potential difference of ##50V##, somehow I need to convert this into an potential energy but I have no idea how to do that so I don't even know if ##E>V_0## or not and the above formulas are applicable.

Assuming they are I can simply ##R## as
##R = \left( \frac{\sqrt{E}-\sqrt{E-V_0}}{\sqrt{E}-V_0} \right)^2##.
Now I don't know ##V_0## but let's guess ##V_0 = 50eV## (seeing the number 50 in the question!) then
##R=\left( \frac{\sqrt{100}-\sqrt{50}}{\sqrt{100}+\sqrt{50}} \right)^2\approx 0.3##
which agrees with the answer to the exercise but I have no idea if ##V_0 = 50eV## or why that is.
 
Physics news on Phys.org
Potential energy is ##qV## !
 
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BvU said:
Potential energy is ##qV## !
Thanks, I suspected that but wasn't sure!
 
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